우당탕탕 RUST 도전기 (1)

FE 개발자의 막무가내 Rust 도전기

• 8진수 2진수 (#1212)

use std::io::{self, BufRead};

pub fn main() {
  let mut input= String::new();
  io::stdin().lock().read_line(&mut input).unwrap();
  let input = input.trim();
  let mut res = String::new();
  let arr = ["000", "001", "010", "011", "100", "101", "110", "111"];
  for o_num in input.chars() {
    res.push_str(change_o_to_b(o_num, arr));
  }
  if res == "000" {
    println!("{}", 0)
  } else {
    println!("{}", res.trim_start_matches("0"));
  }
}

fn change_o_to_b(oNum: char, binArr: [&str; 8])-> &str {
  let idx = oNum.to_digit(8).unwrap() as usize;
  binArr[idx]
}

• DNA 해독 (#1672)

use std:: io::{self, BufRead};

pub fn main() {
  let mut input = io::stdin().lock().lines();
  let N: i32 = input.next().unwrap().unwrap().parse().unwrap();
  let yumgi: i32 = input.next().unwrap().unwrap();
  let table = [0,A,C,A,G,0,T,0,A,C,0,0,G,0,0,0,T];
  let mut res;
  for i in (1..=N).rev() {

  }
  println!("{}",max_val);
  println!("{}",max_idx);
}

• 주사위 세개 (#2480)

use std::{cmp::max, io::{self, BufRead}};

pub fn main() {
  let mut input= String::new();
  io::stdin().lock().read_line(&mut input).unwrap();
  let numbers: Vec<i32> = input
    .split_whitespace() // 공백을 기준으로 분할
    .map(|s| s.parse().unwrap()) // 각 부분 문자열을 숫자로 변환
    .collect(); // 결과를 벡터에 수집

  if numbers[0] == numbers[1] && numbers[1] == numbers[2] {
    println!("{}", numbers[0] * 1000 + 10000);
  } else if numbers[0] == numbers[1] || numbers[0] == numbers[2] {
    println!("{}", (numbers[0] * 100 + 1000));
  } else if numbers[1] == numbers[2] {
    println!("{}", (numbers[1] * 100 + 1000));
  } else {
    println!("{}", max(max(numbers[0], numbers[1]), numbers[2]) * 100);
  }
}

• 최대값 (#2562)

use std:: io::{self, BufRead};

pub fn main() {
  let mut input = io::stdin().lock().lines();
  let mut max_val = 1;
  let mut max_idx = 1;
  for i in 0..9 {
    let num: i32 = input.next().unwrap().unwrap().parse().unwrap();
    if num > max_val {
      max_val = num;
      max_idx = i + 1
    }
  }
  println!("{}",max_val);
  println!("{}",max_idx);
}